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57x=125+4x^2
We move all terms to the left:
57x-(125+4x^2)=0
We get rid of parentheses
-4x^2+57x-125=0
a = -4; b = 57; c = -125;
Δ = b2-4ac
Δ = 572-4·(-4)·(-125)
Δ = 1249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-\sqrt{1249}}{2*-4}=\frac{-57-\sqrt{1249}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+\sqrt{1249}}{2*-4}=\frac{-57+\sqrt{1249}}{-8} $
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